glmdenoise.utils.isrowvector module

glmdenoise.utils.isrowvector.isrowvector(m)[source]

Check if the array has only one dimension

f = isrowvector(m)

function f = isrowvector(m)

<m> is a matrix

return whether <m> is 1 x n where n >= 0. specifically: f = isvector(m) & size(m,1)==1;

example: isrowvector([[1,2]]) isrowvector([[1]]) isrowvector(np.zeros(1)) not isrowvector([])